Who Played BothPlay

Players who played for both Brentford and Coventry City

According to Wikidata and Wikipedia, 38 players have played for both Brentford and Coventry City. The best known: Jordan Henderson, Callum Wilson and Chuba Akpom.

Last updated:

The list

#PlayerBornBrentfordCoventry City
1Jordan Henderson19902025–20262009
2Callum Wilson1992?–2009–2014
3Chuba Akpom199520142014
4Stephen Hunt19812001–20052016
5Frank Onyeka1998—?–
6Kenny Sansom195819931991–1993
7Hermann Hreiðarsson19741998–19992012
8Clinton Morrison197920122008–2010
9Daniel Bentley19932016–2019?–
10Blair Adams199120112012–2014
11Nick Proschwitz19862014–20152015
12Jake Bidwell19932011–2013?–
13Stephen Wright19802010–20112008–2010
14Ted Hanney1889—1919–1921
15Jay Tabb19842000–20062006–2009
16Dean Holdsworth19681988–19922002–2003
17John Salako19692004–20051995–1998
18Gerry Baker193819691967–1970
19Martin Grainger19721993–19962004
20Zbigniew Kruszyński19601992–19931993–1994
21Jack Astley19091933–19361936–1939
22Jimmy Holmes195319831970–1977
23Bill Glazier194319751964–1975
24Robbie Simpson19852010–20112007–2009
25Bert Powell18801915–19191909–1910
26George Kirby19331968–19691964
27Fred Howe18951921–19221919–1920
28Walter Metcalf19101934–19371937–1946
29Paul Watson19751997–19992005
30Wayne Turner19611986–19871985–1986
31Alex McCulloch1886——
32Zain Westbrooke19962015–20182018
33Craig Pead19812007–20091999–2005
34Harry Stanford18991925–19261927
35John Thomson18961925–19261928
36Jack Doran1896—1914
37Perry Suckling196519911983–1986
38Ted Winship19011926–19291922–1924

Which way they moved

Play it

In Who Played Both you and your opponent secretly pick a club each. If the clubs are Brentford and Coventry City, the first to name one of the players above in 15 seconds wins the round.

More pairs with Brentford

More pairs with Coventry City

Türkçe: Brentford ve Coventry City ortak oyuncuları

Source: Wikidata (CC0) and Wikipedia club articles. Youth spells and appearances that look unplayed are left out; volunteer-kept records can contain gaps or errors.